Statistics
You are a robotics engineer working for a large tech company. For one of your artificially intelligent robots, you are looking to see if the size of the data file used to train the robot is predictive of the time the robot takes to complete a maze. You are going to collect a random sample of 7 attempts at completing the maze. You will note for each attempt the size of the data file (denoted by x, in MB) and the time (denoted by y, in seconds) to complete the maze. You will also note the product x*y of the size of the data file and the completion time for each attempt. Data file size, x (in MB): 123.8, 99.6, 198.1, 42.5, 61.3, 164.2, 85.4 Completion time, y (in seconds): 134, 253, 85, 386, 423, 157, 226 xy: 16,589.2, 25,198.8, 16,838.5, 16,405, 25,929.9, 25,779.4, 19,300.4 Find: n, x_bar, y_bar, s_x, s_y, sum(xy) Then compute: - Sample correlation coefficient r - Slope b_1 - y-intercept b_0 - Regression equation: y_hat = b_0 + b_1*x
Step-by-step solution with explanation
Final Answer
, MB, sec, , , ; (strong negative linear relationship); ; ; Regression equation:Step-by-step solution
Understanding this problem
Learning Insight
The correlation coefficient r measures how tightly the data clusters around a straight line, ranging from −1 to +1. A negative r here means bigger training files are linked to faster maze completion — perhaps larger files give the robot better 'knowledge.' The regression line minimizes the total squared vertical distances from each data point to the line, which is why it is called 'least-squares.'Quick Tip
Remember: slope = r × (s_y / s_x). If you already have r and both standard deviations, the slope is one quick multiplication. Then get b₀ by plugging the two means into ȳ = b₀ + b₁x̄ and solving for b₀.Common Mistake
Students often use n instead of n−1 when computing s_x and s_y for a sample. Always use n−1 in the denominator for sample standard deviation; using n gives the population standard deviation and will make your r and slope slightly off.